.33x^2-7=43

Solution for .33x^2-7=43 equation:

.33x^2-7=43

We move all terms to the left:

.33x^2-7-(43)=0

We add all the numbers together, and all the variables

.33x^2-50=0

a = .33; b = 0; c = -50;
Δ = b2-4ac
Δ = 02-4·.33·(-50)
Δ = 66
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{66}}{2*.33}=\frac{0-\sqrt{66}}{0.66}
=-\frac{\sqrt{}}{0.66}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{66}}{2*.33}=\frac{0+\sqrt{66}}{0.66}
=\frac{\sqrt{}}{0.66}
$